8x^2+132x+288=0

Solution for 8x^2+132x+288=0 equation:

8x^2+132x+288=0

a = 8; b = 132; c = +288;
Δ = b2-4ac
Δ = 1322-4·8·288
Δ = 8208
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8208}=\sqrt{144*57}=\sqrt{144}*\sqrt{57}=12\sqrt{57}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(132)-12\sqrt{57}}{2*8}=\frac{-132-12\sqrt{57}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(132)+12\sqrt{57}}{2*8}=\frac{-132+12\sqrt{57}}{16}
$